Integrand size = 17, antiderivative size = 19 \[ \int \frac {\left (b x^2+c x^4\right )^3}{x^{15}} \, dx=-\frac {\left (b+c x^2\right )^4}{8 b x^8} \]
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Time = 0.01 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {1598, 270} \[ \int \frac {\left (b x^2+c x^4\right )^3}{x^{15}} \, dx=-\frac {\left (b+c x^2\right )^4}{8 b x^8} \]
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Rule 270
Rule 1598
Rubi steps \begin{align*} \text {integral}& = \int \frac {\left (b+c x^2\right )^3}{x^9} \, dx \\ & = -\frac {\left (b+c x^2\right )^4}{8 b x^8} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(43\) vs. \(2(19)=38\).
Time = 0.01 (sec) , antiderivative size = 43, normalized size of antiderivative = 2.26 \[ \int \frac {\left (b x^2+c x^4\right )^3}{x^{15}} \, dx=-\frac {b^3}{8 x^8}-\frac {b^2 c}{2 x^6}-\frac {3 b c^2}{4 x^4}-\frac {c^3}{2 x^2} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(35\) vs. \(2(17)=34\).
Time = 0.04 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.89
method | result | size |
gosper | \(-\frac {4 c^{3} x^{6}+6 b \,c^{2} x^{4}+4 b^{2} c \,x^{2}+b^{3}}{8 x^{8}}\) | \(36\) |
default | \(-\frac {c^{3}}{2 x^{2}}-\frac {b^{3}}{8 x^{8}}-\frac {b^{2} c}{2 x^{6}}-\frac {3 b \,c^{2}}{4 x^{4}}\) | \(36\) |
risch | \(\frac {-\frac {1}{2} c^{3} x^{6}-\frac {3}{4} b \,c^{2} x^{4}-\frac {1}{2} b^{2} c \,x^{2}-\frac {1}{8} b^{3}}{x^{8}}\) | \(37\) |
parallelrisch | \(\frac {-4 c^{3} x^{6}-6 b \,c^{2} x^{4}-4 b^{2} c \,x^{2}-b^{3}}{8 x^{8}}\) | \(38\) |
norman | \(\frac {-\frac {1}{8} b^{3} x^{6}-\frac {1}{2} c^{3} x^{12}-\frac {3}{4} b \,c^{2} x^{10}-\frac {1}{2} b^{2} c \,x^{8}}{x^{14}}\) | \(40\) |
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Leaf count of result is larger than twice the leaf count of optimal. 35 vs. \(2 (17) = 34\).
Time = 0.25 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.84 \[ \int \frac {\left (b x^2+c x^4\right )^3}{x^{15}} \, dx=-\frac {4 \, c^{3} x^{6} + 6 \, b c^{2} x^{4} + 4 \, b^{2} c x^{2} + b^{3}}{8 \, x^{8}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 37 vs. \(2 (15) = 30\).
Time = 0.13 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.95 \[ \int \frac {\left (b x^2+c x^4\right )^3}{x^{15}} \, dx=\frac {- b^{3} - 4 b^{2} c x^{2} - 6 b c^{2} x^{4} - 4 c^{3} x^{6}}{8 x^{8}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 35 vs. \(2 (17) = 34\).
Time = 0.20 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.84 \[ \int \frac {\left (b x^2+c x^4\right )^3}{x^{15}} \, dx=-\frac {4 \, c^{3} x^{6} + 6 \, b c^{2} x^{4} + 4 \, b^{2} c x^{2} + b^{3}}{8 \, x^{8}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 35 vs. \(2 (17) = 34\).
Time = 0.28 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.84 \[ \int \frac {\left (b x^2+c x^4\right )^3}{x^{15}} \, dx=-\frac {4 \, c^{3} x^{6} + 6 \, b c^{2} x^{4} + 4 \, b^{2} c x^{2} + b^{3}}{8 \, x^{8}} \]
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Time = 0.03 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.95 \[ \int \frac {\left (b x^2+c x^4\right )^3}{x^{15}} \, dx=-\frac {\frac {b^3}{8}+\frac {b^2\,c\,x^2}{2}+\frac {3\,b\,c^2\,x^4}{4}+\frac {c^3\,x^6}{2}}{x^8} \]
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